Thursday, November 18, 2010

Physics Problem(Research Balloon)?

A research balloon of total mass 330 kg is descending vertically with a downward acceleration of 0.1 m/s2. How much ballast must be thrown from the car to give the balloon an upward acceleration equal to 0.7 m/s2, presuming that the upward lift of the balloon does not change.Physics Problem(Research Balloon)?
Let F be the upward lift..so m*g - F = m*a =%26gt; F = m*g - m*a = m*(g-a) = 330*(9.8-.1) =

F = 3201N



Now we want a to be upward and = 0.7m/s^2 ...so F - m*g = m*a

F = m*(g+a) so m = F/(g+a) = 3201/(9.8+.7) = 305kg



Therefore 330 -305 = 25kg of ballast must be thrown over

CAN SOMEBODY PLEASE ANSWER THESE!?!?! 10POINTS?

6. What happens when you compress a gas? (Points: 3)

You decrease its temperature.

You decrease its pressure.

You increase its volume.

You increase its density.





7. In the Gas Laws lab, you changed temperature to change __________. (Points: 3)

gravity



volume



pressure







8. Which of the following is the most accurate statement concerning volume and pressure of a gas? (Points: 3)

Volume of a gas is always greater than pressure of that gas in any container.

Volume of a gas is directly proportional to pressure of that gas in any container.

Volume of a gas is inversely proportional to pressure of that gas in any container.

Volume of a gas is equal to pressure of that gas in any container.





9. What is the temperature of a gas in which the atoms are moving very, very slowly? (Points: 3)

room temperature

cold

hot





10. Which of the following measures atmospheric pressure? (Points: 3)

a barometer

a thermometer

a ballast tank





11. How is pressure measured? (Points: 3)

Pressure is measured as force per inch.

Pressure is measured as force per gram.

Pressure is measured as force per unit area.

Pressure is measured as force divided by massCAN SOMEBODY PLEASE ANSWER THESE!?!?! 10POINTS?
dude, google is amazing and wont get pissed off about 10 freaking questions.CAN SOMEBODY PLEASE ANSWER THESE!?!?! 10POINTS?
10 th one is barometer

Vertical motion with constant acceleration?

A research balloon of total mass 260 kg is descending vertically with a downward acceleration of 3.7 m/s2. How much ballast must be thrown from the car to give the balloon an upward acceleration equal to 1.1 m/s2, presuming that the upward lift of the balloon does not changeVertical motion with constant acceleration?
Let F be the upward lift..so m*g - F = m*a =%26gt; F = m*g - m*a = m*(g-a) = 260*(9.8-3.7) =

F = 1586N



Now we want a to be upward and = 1.1m/s^2 ...so F - m*g = m*a

F = m*(g+a) so m = F/(g+a) = 1586/(9.8+1.1) = 146kg



Therefore 260 -146 = 114kg of ballast must be thrown over

H I D headlights color contrast ?

I just bought a set of HID bulbs in a wiring kit from eBay and I need to know if I can change the color contrast to blue purple like 8000k-12000k with a different ballast, or do I have to use the color code on my lights it says it is 35w 6000k color contrast and it's diamond white will I blow them up! just want to see if any one can help me before I order thanks.

dose any one know how this works stuff works?H I D headlights color contrast ?
ballasts are color temperature specific (8000k ballast with 8000k bulb), 6000k is bright white, and 10-12000k is a cool color, but doesn't light very well. honestly, if you're using oem headlights, i would suggest sticking with halogen bulbs, if you go HID in a oem headlight, you will illuminate everything, and not just the road, you will basically just blind oncoming drivers...i have oem headlights and i use %26quot;fake HID%26quot; bulbs, which are colored to 10000k, but are halogen bulbs and still project the light correctly. HID headlight housings are specifically designed to project HID light onto the road.



I got my bulbs from HIDLOOK.COM... they also sell HID kits if you still want to go that route, or you can get super white PIAA bulbs, or even silvania silverstars from walmart...those work very well as well.

Research balloon, could not find any correct answer?

A research balloon of total mass 415 kg is descending vertically with a downward acceleration of 1.4 m/s2. How much ballast must be thrown from the car to give the balloon an upward acceleration equal to 4.1 m/s2, presuming that the upward lift of the balloon does not change



just answer it and ill give you my life :x

Research balloon, could not find any correct answer?
The buoyant force = m1(g-1.4) = 3486 N

We want m2(g+4.1) = 3486 N ==%26gt; m2 = 3486/(13.9) = 250.79 kg.

So drop 164.21 kg.

I'll settle for your first-born.Research balloon, could not find any correct answer?
Oh, the flattery! Thanks.

Report Abuse

  • advice for going to a new school
  • good conversation with
  • I'm replacing an old point type distributor with an HEI Dist.on a 69 Chevy C/10 Truck. How do i wire it in

    I need wiring instructions for the new High Energy Ignition distributor. I am installing it into a 1969 Chevy C/10 pickup truck with a 350 Eng. Is there anything i should know about the wiring and my spark plug gap was .035 will i be changing the gap to .040 or .060 and do I need to run my 12 volt power wire through a ballast resistor before I connect it to the distributorI%26039;m replacing an old point type distributor with an HEI Dist.on a 69 Chevy C/10 Truck. How do i wire it in
    SIMPLEST option-------%26gt;

    use a test light and locate a fuse in the fuse block that is %26quot;Hot%26quot; only when the key is in the %26quot;Run%26quot; and %26quot;Start%26quot; positions. It should not be %26quot;Hot%26quot; in the %26quot;Acc%26quot; position. There used to be two connectors on the old fuse blocks that would work this way.

    Run a 12 wire from the terminal (%26quot;Hot%26quot; side of the fuse, not the fused side) to the %26quot;+%26quot; terminal of the HEI dist.

    This distributor requires full battery and charging voltage. Use NO resistor.

    When the HEI first came out in the early '70s, the plug gap was recommended from .045%26quot; all the way to .80%26quot;, and there were fouling issues. G.M. came out with a TSB to run the plugs at .035%26quot;, and ultimately recommended .045%26quot; for most applications.



    Good LuckI%26039;m replacing an old point type distributor with an HEI Dist.on a 69 Chevy C/10 Truck. How do i wire it in
    try 45 on the gap and see how it works and no don't use a resistor thats only for points.I%26039;m replacing an old point type distributor with an HEI Dist.on a 69 Chevy C/10 Truck. How do i wire it in
    If you had an external module cut the power wire for it (It should be the biggest one) and use that to power the dizzy. If you have a tach use the NEG wire from your coil and connect it to the TACH terminal of the HEI.



    Other wise any 12V when the key to ON wire will do.I%26039;m replacing an old point type distributor with an HEI Dist.on a 69 Chevy C/10 Truck. How do i wire it in
    there should be red and yellow-or red and brown wires goin to your points style seperate coil-on the hei cap it should be marked with 2-3 wire inputs plus your plug that goes from your cap to your distributer-really all you need is the red power wire to go where it says 12v+-dont plug anything into the place marked tach-thats for a tachometer-not another power source-if it has a placed mark ground or 12v- thats where you hook the yellow or brown wire-but most are self grounded and just have a tach and 12v+ input-hope this helps ya-also just have autozone look up the gap on like a 85 chevy truck-these have hei and will give you the proper gap-i think when i changed mine it went up to 43 or 45 gap

    Vertical Motion With Constant Acceleration?

    A research balloon of total mass 285 kg is descending vertically with a downward acceleration of 2.7 m/s2. How much ballast must be thrown from the car to give the balloon an upward acceleration equal to 4.2 m/s2, presuming that the upward lift of the balloon does not change.Vertical Motion With Constant Acceleration?
    Direct answer --%26gt; 102 kg



    Second Law



    a1 = 2.7 m/s^2

    a2 = 4.2 m/s^2

    m1 = 285 kg

    m2 = 285 kg - x



    F = F



    m1a1 = m2a2



    (285 kg) * (2.7 m/s^2) = (285 - x) * (4.2 m/s^2)

    (769.5 N) = (285 - x) * (4.2 m/s^2)

    183.2 kg = 285 kg - x



    x = 285 kg - 183.2 kg

    x = 102 kg